Yes.
You feel the weightlessness with your inner ear, and the pressure with other parts of your body, so before you're crushed, you can experience them simultaneously.
Earth Should Be Hollow
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Yes.
You feel the weightlessness with your inner ear, and the pressure with other parts of your body, so before you're crushed, you can experience them simultaneously.
Both. You feel the pressure of all that material, but you are not being effected by gravity.
In principle it shoul feel similar then to floating at great depth underwater x1,000,000 or so XD
Better hold your breath then.
Better have some Unobtainium handy, is all I'll say...
Wouldn't the trapped star's gravitational force work equally on opposites sides of the sphere and therefore keep itself centered in a manner of speaking?Bob
Bob
The net field inside the shell is zero. It's the same reason that the Ringworld is unstable.
http://en.wikipedia.org/wiki/Gauss's_law_for_gravity#Spherically_symmetric_mass_distribution
In any case, Dyson's original concept was not a solid shell but a swarm.
Not exactly. Actually, the star will very strongly attract the dyson sphere -- and anyone on it -- at all times. The sphere would have to be built very strong in order for the star's gravity to not collapse it; moreover, any perturbation in the sphere's position will cause the star to pull more strongly on one side than on the others, and eventually it will hit the side of the sphere.
Maybe that's why the Jenolan Sphere was abandoned? Artificial gravity malfunctioned and everyone living there fell into the sun?
Sigh, wrong. See above.
A spherical shell (itself possessing a spherically symmetric distribution of mass) with an additional point mass inside is not empty and it violates the conditions of such a spherical shell with no additional point mass. There is a field inside a spherical shell that contains an additional point mass, namely that of the additional point mass itself.
Actually, Ringworld WOULD be stable if you spun it at its orbital velocity for that radius (also, the net gravitational field inside a ring is NOT zero, but would be a torroidal field in which observers along the plane of the ring would be attracted to the inner surface of the ring and observers above or below would be attracted towards the center by a degree equal to the magnitude of their distance from the plane.
Bob
The net field inside the shell is zero. It's the same reason that the Ringworld is unstable.
Please provide more content, less mockery. This shouldn't be construed as a validation of the OP's ideas but if you want to discuss it, discuss it. If not, it's better to hold your tongue.
Thank you.
ok, sorry.
its just if theres no mass in the middle, theres no gravity to hold the outside in place, which would mean theres no outside. therefore the earth doesn't exist.
or just:
its just if theres no mass in the middle, theres no gravity to hold the outside in place, which would mean theres no outside. therefore the earth doesn't exist.
or just:
Re-read my original premise.... the gravity was there to begin with because at the beginning the Earth wasn't hollow it was whole, rocks combined together and the Earth got bigger. The hollowing took place as the Earth got bigger because the centre of gravity would have moved outwards from the centre as more mass arrived on the surface as opposed to the limited amount of mass at the centre.
When I say it's hollow I don't mean super hugely insanely hollow, I mean somewhat hollow.
As the centre of gravity moved outwards that means there is a solid outer mantle, a magma layer where the gravity is and then a lower solid layer. The lower layer likely spinning at a faster rate than the upper layer possibly an explanation for the magnetic field.
Anyway I concede defeat on the matter, many people have raised good points within the thread.
Actually, Ringworld WOULD be stable if you spun it at its orbital velocity for that radius (also, the net gravitational field inside a ring is NOT zero, but would be a torroidal field in which observers along the plane of the ring would be attracted to the inner surface of the ring and observers above or below would be attracted towards the center by a degree equal to the magnitude of their distance from the plane.
Bob
The net field inside the shell is zero. It's the same reason that the Ringworld is unstable.
The ring is different from the sphere. Inside the sphere the gravitational field of the sphere all cancels out, and the net gravitational pull of the sun on the sphere is zero regardless of where the sun is placed inside the sphere. So the Dyson sphere has neutral stability everywhere. If the sun drifts out of position, there is no force that corrects or enhances the drift. A tiny push, over time, would have the sphere and sun collide.
The ring, in contrast, has a strong negative stability. If the sun is a bit closer to one side of a ring, then it pulls that side of the ring ever closer.
The difference is that when the sphere moves out of position, the big fat circumference of the sphere that's moved away from being centered on the sun has more relative mass than a center segment of the ring, which just has the same mass as any other position on the ring. When you try to balance a ring, but have it a bit off-center, the mass error relates to arc lengths, whereas with a sphere the mass error relates to surface area. When you crunch this through a square law field, you get the difference between a sphere (neutral stability) and a ring (negative stability).
Early Ringworld fans chewed Larry Niven a new one over that.
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