I'm with Jadzia on this one. But first, I must ask a few questions (just to make sure). Does the Guru tell each day:"There is someone with blue eyes", or just on the first day, and if he says it every day, does he on every new day speak about another person, as in: "There is another one with blue eyes".
If it's just once, or just: "I see someone with blue eyes", I know what is the fault with the "solution"(I hope) and I will try to explain it, and then as I understand it, nobody will ever leave.
But I'll wait for the answer first, in order not to type in vain.
Edited to add (Ahh... what the hell
):
I can't bother with reading 5 pages at the moment, so I hope this is the accepted "solution":
I believe the riddle is flawed.

If it's just once, or just: "I see someone with blue eyes", I know what is the fault with the "solution"(I hope) and I will try to explain it, and then as I understand it, nobody will ever leave.

But I'll wait for the answer first, in order not to type in vain.
Edited to add (Ahh... what the hell

I can't bother with reading 5 pages at the moment, so I hope this is the accepted "solution":
The problem with the bolded part is the following. It carries the assumtion that even in the three case scenario the two people "look at each other"-thinking still stands ground, but it doesn't 'cause it was based on the fact there were only two of them, and now there aren't. I mean, it's obvious. Now there are three of them on the first night. Each one of them sees two blue eyed people. Now the statement:"There is someone with blue eyes", means nothing they already don't know, and the fact nobody leaves doesn't tell them anything new either. Now they can't conlude: if the other guy hasn't left it's because I have blue eyes as well, so he thought the guru spoke about me, because there are now two guys other than me, and the whole reasoning falls flat on its head.Exactly.
Each of the blue eyed-people knows that there are 99 blue-eyed people on the island (plus themselves but they don't know that).
If there's only one blue-eyed person on the island then he sees nobody with blue-eyes. Which means he can leave on the first night.
But that's not the case.
If there are 2 blue-eyed persons each of them sees 1 blue-eyed person on the island. Since they both still see one they can't be sure of their own colour. So neither of them leaves.
If neither of them leaves they know that they must both have blue eyes because nobody else does. They leave on the 2nd night.
If there are three blue-eyed people each one of them can see 2 blue-eyed people. If those two blue-eyed people haven't left on the 2nd day then the 3rd person knows that he must have blue eyes, too. They all leave on the third day.
Rinse and repeat. After 99 days everybody will know if he or she has blue eyes because nobody has left by then. They will know that in addition to the 99 blue-eyed people each of them sees there must be a 100th person. So they all leave on the 100th day.
I resisted the urge to google it but I think it should be pretty correct.
I believe the riddle is flawed.


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