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 The Trek BBS Confused about E=mc²

 Science and Technology "Somewhere, something incredible is waiting to be known." - Carl Sagan.

 July 18 2013, 11:32 PM #1 Lt. Uhura-Brown Lieutenant Commander   Location: New Zealand Confused about E=mc² I was thinking about the famous equation E=mc² the other day, when I realised I didn't actually understand it, or rather, the units used. It seems to me that Joules = (volume multiplied by density) multiplied by (300 million meters divided by 1 second) multiplied by (300 million meters divided by 1 second)? I know there's something I must be missing, but I can't wrap my head around how it all fits together.
 July 19 2013, 12:47 AM #2 Christopher Writer Re: Confused about E=mc² Mass is a basic quantity that doesn't have to be broken down; kilograms are generally the preferred unit. A joule is a newton-meter, and a newton is a kilogram-meter per second squared; so that means joules are (kg x m/s^2) x m = kg x m^2/s^2 = kg x (m/s)^2, which is mass (kg) times velocity (m/s) squared, with the velocity being the speed of light. So a mass of 1 kg, if converted to energy, would come out to 1 kg x (3 x 10^8 m/s)^2 = 9 x 10^16 J. __________________ Written Worlds -- Christopher L. Bennett's blog and webpage
 July 19 2013, 08:04 AM #3 Asbo Zaprudder Rear Admiral     Location: On the beach Re: Confused about E=mc² ^What Christopher says. Also, in particle physics and astrophysics, the units commonly used are electron volts (eV) for energy and eV/c² for mass -- the latter usually being abbreviated to eV if natural units are used which set c=1. One volt (V) is defined as being the potential difference when one coulomb (C) of charge crosses that potential resulting in a change of one joule (J) of energy. One electron volt is defined as the magnitude of the energy change of an electron moving through an potential difference of one volt. So 1 eV = 1.602x10^−19 J given that the magnitude of the charge on the electron is 1.602×10^−19 C (the charge is actually a negative quantity for electrons and positive for positrons, of course). Last edited by Asbo Zaprudder; July 19 2013 at 08:22 AM.

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